What is the domain of y=(x+1)/(x^2-9x) ?

The domain of y=(x+1)/(x^2-9x) is x 9

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domain of y=(x+1)/(x^2-9x)

domain

y = \frac{x + 1}{x ^{2} - 9 x}

x < 0 or 0 < x < 9 or x > 9

Interval Notation

(- \infty, 0) \cup (0, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

x = 9, x = 0

The function domain

x < 0 or 0 < x < 9 or x > 9

f (x) = - 2 lo g_{e} (x)

f (x) = \frac{x ^{2}}{x ^{2} - 1}

- \frac{2 ( x - 5 ) ( x - 3 )}{( x + 5 ) ^{2}}

f (x) = \frac{x ^{3} - x + 3}{x ^{2} - 1}

f (x) = ln (x + 5) - 3

What is the domain of y=(x+1)/(x^2-9x) ?
The domain of y=(x+1)/(x^2-9x) is x<0\lor 0<x<9\lor x>9