What is the domain of y=(4x+1)/(sqrt(x-2)) ?

The domain of y=(4x+1)/(sqrt(x-2)) is x>2

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domain of y=(4x+1)/(sqrt(x-2))

domain

y = \frac{4 x + 1}{x - 2}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

\frac{8 x + 6}{9 x - 5}

\frac{- 2 x + 5}{4 x + 3}

x^{2} - 6 x + 45

f (x) = (3 x - 5) (2 x + 1)

\frac{- x ^{3} - 2 x ^{2} + 4 x + 1}{x - 1}

What is the domain of y=(4x+1)/(sqrt(x-2)) ?
The domain of y=(4x+1)/(sqrt(x-2)) is x>2