What is the domain of sqrt(25-x-9x^2) ?

The domain of sqrt(25-x-9x^2) is (-sqrt(901)-1)/(18)<= x<= (sqrt(901)-1)/(18)

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domain of sqrt(25-x-9x^2)

domain

25 - x - 9 x^{2}

\frac{- 901 - 1}{18} \leq x \leq \frac{901 - 1}{18}

Interval Notation

[\frac{- 901 - 1}{18}, \frac{901 - 1}{18}]

Solution steps

Find non-negative values for radicals:

\frac{- 901 - 1}{18} \leq x \leq \frac{901 - 1}{18}

The function domain

\frac{- 901 - 1}{18} \leq x \leq \frac{901 - 1}{18}

\frac{6 - 7 x}{5 + 4 x}

f (x) = \frac{( 2 x ^{2} + 5 x + 3 )}{∣ x + 1 ∣}

f (x) = \frac{x + 7}{x - 9}

\frac{7 - x ^{2}}{x ^{2} + 2 x - 15}

f (x) = \frac{15}{\frac{3}{x} - 1}

What is the domain of sqrt(25-x-9x^2) ?
The domain of sqrt(25-x-9x^2) is (-sqrt(901)-1)/(18)<= x<= (sqrt(901)-1)/(18)