What is the domain of y=(3x^2+7x-1)/(x+1) ?

The domain of y=(3x^2+7x-1)/(x+1) is x -1

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domain of y=(3x^2+7x-1)/(x+1)

domain

y = \frac{3 x ^{2} + 7 x - 1}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

5 lo g_{e} (x - 7) - 1

h (x) = 2 x - x + 1

f (x) = (x^{2} + 12) (144 - x^{2})

f (x) = \frac{5 x + 7}{2 x + 8}

What is the domain of y=(3x^2+7x-1)/(x+1) ?
The domain of y=(3x^2+7x-1)/(x+1) is x<-1\lor x>-1