What is the domain of f(x)=(3x-6)/(8x^2+6x-5) ?

The domain of f(x)=(3x-6)/(8x^2+6x-5) is x 1/2

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domain of f(x)=(3x-6)/(8x^2+6x-5)

domain

f (x) = \frac{3 x - 6}{8 x ^{2} + 6 x - 5}

x < - \frac{5}{4} or - \frac{5}{4} < x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

(- \infty, - \frac{5}{4}) \cup (- \frac{5}{4}, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{2}, x = - \frac{5}{4}

The function domain

x < - \frac{5}{4} or - \frac{5}{4} < x < \frac{1}{2} or x > \frac{1}{2}

f (x) = \frac{- 4 x + 13}{2 x - 5}

f (x,) = \frac{( x ^{2} - 4 )}{∣ x - 2 ∣}

ln (- x^{2} + 1)

y = \frac{3}{5 + x}

f (x) = 2 ∣ x ∣ + 3 - x^{2}

What is the domain of f(x)=(3x-6)/(8x^2+6x-5) ?
The domain of f(x)=(3x-6)/(8x^2+6x-5) is x<-5/4 \lor-5/4 <x< 1/2 \lor x> 1/2