What is the domain of f(x)=(x+1)/(x^2+5x+4) ?

The domain of f(x)=(x+1)/(x^2+5x+4) is x -1

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domain of f(x)=(x+1)/(x^2+5x+4)

domain

f (x) = \frac{x + 1}{x ^{2} + 5 x + 4}

x < - 4 or - 4 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 4) \cup (- 4, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 4

The function domain

x < - 4 or - 4 < x < - 1 or x > - 1

y = - 3 (x - 2)^{2} + 4

\frac{8 x + 3}{2 x - 6}

f (x) = \frac{( 5 - x )}{x}

1^{x}

(5 - 9 t)^{\frac{9}{2}}

What is the domain of f(x)=(x+1)/(x^2+5x+4) ?
The domain of f(x)=(x+1)/(x^2+5x+4) is x<-4\lor-4<x<-1\lor x>-1