What is the domain of (9x^2-8x-7)/((x+3)(4x-2)) ?

The domain of (9x^2-8x-7)/((x+3)(4x-2)) is x 1/2

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domain of (9x^2-8x-7)/((x+3)(4x-2))

domain

\frac{9 x ^{2} - 8 x - 7}{( x + 3 ) ( 4 x - 2 )}

x < - 3 or - 3 < x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

(- \infty, - 3) \cup (- 3, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3, x = \frac{1}{2}

The function domain

x < - 3 or - 3 < x < \frac{1}{2} or x > \frac{1}{2}

9 - 8 x

f (x) = \frac{x ( x + 2 )}{3 ( x - 7 )}

f (x) = arccsch (x)

y = lo g_{3} (x^{2} - 4)

y = - 1 + 9

What is the domain of (9x^2-8x-7)/((x+3)(4x-2)) ?
The domain of (9x^2-8x-7)/((x+3)(4x-2)) is x<-3\lor-3<x< 1/2 \lor x> 1/2