What is the domain of f(x)=sqrt(2-(x^2-x)) ?

The domain of f(x)=sqrt(2-(x^2-x)) is -1<= x<= 2

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domain of f(x)=sqrt(2-(x^2-x))

domain

f (x) = 2 - (x^{2} - x)

- 1 \leq x \leq 2

Interval Notation

[- 1, 2]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 2

The function domain

- 1 \leq x \leq 2

\frac{1}{x + 4} - 2

f (x) = \frac{3 x ^{2} - 2}{x ^{2} - 25}

f (x) = \frac{x - 2}{2 ( 2 x - 3 )}

ln (\frac{1}{1 - x})

f (x) = \frac{4 x}{10 - 2 x - 46}

What is the domain of f(x)=sqrt(2-(x^2-x)) ?
The domain of f(x)=sqrt(2-(x^2-x)) is -1<= x<= 2