What is the domain of 1/(sqrt(3x^2-3x-6)) ?

The domain of 1/(sqrt(3x^2-3x-6)) is x 2

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domain of 1/(sqrt(3x^2-3x-6))

domain

\frac{1}{3 x ^{2} - 3 x - 6}

x < - 1 or x > 2

Interval Notation

(- \infty, - 1) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 2

Find undefined (singularity) points:

x = 2, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 2

f (x) = \frac{x ^{2} - 3 x - 10}{x ^{2} - 7 x - 18}

f (x) = (- 1.3) (0.2) (1.1)

\frac{x + 5}{x ( x + 7 )}

x - 2 x + 3

f (x) = \frac{4 - x}{x - 3}

What is the domain of 1/(sqrt(3x^2-3x-6)) ?
The domain of 1/(sqrt(3x^2-3x-6)) is x<-1\lor x>2