What is the domain of f(x)=(sqrt(x-1))^2 ?

The domain of f(x)=(sqrt(x-1))^2 is x>= 1

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domain of f(x)=(sqrt(x-1))^2

domain

f (x) = (x - 1)^{2}

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

f (x) = \frac{5}{x - 1}

y = lo g_{10} (\frac{x + 4}{x - 2})

g (x) = ∣ 2 x ∣ + 2

\frac{x ( x + 4 )}{- 3 x - 7}

\frac{( x + a ^{2} - a )}{x}

What is the domain of f(x)=(sqrt(x-1))^2 ?
The domain of f(x)=(sqrt(x-1))^2 is x>= 1