What is the domain of f(x)= 1/(\sqrt[3]{(x-4))} ?

The domain of f(x)= 1/(\sqrt[3]{(x-4))} is x 4

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domain of f(x)= 1/(\sqrt[3]{(x-4))}

domain

x < 4 or x > 4

Interval Notation

(- \infty, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4

The function domain

x < 4 or x > 4

f (x) = \frac{x}{2 - 3 x}

f (x) = ln (x - 20)

f (x) = \frac{3}{x ^{2} + 3}

\frac{3 x ^{2} + 5 x - 3}{8 x ^{2}}

f (x) = 25 + 5^{x}

What is the domain of f(x)= 1/(\sqrt[3]{(x-4))} ?
The domain of f(x)= 1/(\sqrt[3]{(x-4))} is x<4\lor x>4