What is the domain of f(x)=(x\sqrt[4]{x(x^2+2)}+1)/x ?

The domain of f(x)=(x\sqrt[4]{x(x^2+2)}+1)/x is x>0

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domain of f(x)=(x\sqrt[4]{x(x^2+2)}+1)/x

domain

x > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

- 2 (x + 3) + 1

f (x) = 5 x^{2} + 3

f (x) = ln (x) - 4

y = \frac{5 x}{x ^{2} + 2}

f (x) = \frac{2 x + 6}{- 3 x + 3}

What is the domain of f(x)=(x\sqrt[4]{x(x^2+2)}+1)/x ?
The domain of f(x)=(x\sqrt[4]{x(x^2+2)}+1)/x is x>0