What is the domain of ((x^2-9))/((x-3)(x+5)) ?

The domain of ((x^2-9))/((x-3)(x+5)) is x 3

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domain of ((x^2-9))/((x-3)(x+5))

domain

\frac{( x ^{2} - 9 )}{( x - 3 ) ( x + 5 )}

x < - 5 or - 5 < x < 3 or x > 3

Interval Notation

(- \infty, - 5) \cup (- 5, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 5

The function domain

x < - 5 or - 5 < x < 3 or x > 3

x^{4} - 4 x^{3} + 1

p (x) = 217 (0.553)^{x}

f (x) = 5 x^{2} + 8

f (x) = \frac{6 x + 5}{x + 1}

1 - x + 3

What is the domain of ((x^2-9))/((x-3)(x+5)) ?
The domain of ((x^2-9))/((x-3)(x+5)) is x<-5\lor-5<x<3\lor x>3