What is the domain of f(x)=sqrt(3x-4)-4x^2-3 ?

The domain of f(x)=sqrt(3x-4)-4x^2-3 is x>= 4/3

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domain of f(x)=sqrt(3x-4)-4x^2-3

domain

f (x) = 3 x - 4 - 4 x^{2} - 3

x \geq \frac{4}{3}

Interval Notation

[\frac{4}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{4}{3}

The function domain

x \geq \frac{4}{3}

f (x) = 3 ln (2 x - 3) + 1

\frac{12 + 4 x}{x - 4}

f (x) = \frac{3 x + 7}{x ^{3} - 27}

f (x) = \frac{x + 6}{x - 3}

y = \frac{1}{\frac{x}{\frac{1}{x} + x}}

What is the domain of f(x)=sqrt(3x-4)-4x^2-3 ?
The domain of f(x)=sqrt(3x-4)-4x^2-3 is x>= 4/3