What is the domain of (2x-3)/(x^2+4x+3) ?

The domain of (2x-3)/(x^2+4x+3) is x -1

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domain of (2x-3)/(x^2+4x+3)

domain

\frac{2 x - 3}{x ^{2} + 4 x + 3}

x < - 3 or - 3 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 3) \cup (- 3, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 3

The function domain

x < - 3 or - 3 < x < - 1 or x > - 1

f (x) = \frac{( x ^{2} + x )}{x ^{2} - 7 x + 10}

f (x) = 2 x^{2} - y + 3 = 0

f (x) = \frac{1}{x ^{2} - 2}

\frac{1}{e ^{2 x}}

f (r) = π r (90 - r^{2})

What is the domain of (2x-3)/(x^2+4x+3) ?
The domain of (2x-3)/(x^2+4x+3) is x<-3\lor-3<x<-1\lor x>-1