What is the domain of f(x)=sqrt((2|x|+3)/(x^2+1)) ?

The domain of f(x)=sqrt((2|x|+3)/(x^2+1)) is -infinity <x<infinity

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domain of f(x)=sqrt((2|x|+3)/(x^2+1))

domain

f (x) = \frac{2 ∣ x ∣ + 3}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 2 \cdot x - \frac{1}{2 \cdot x}

y, y \leq x - 1 - 4

f (x) = - 7^{x}

f (x) = \frac{2 x + 1}{x - 4}

f (x) = \frac{5}{( x ^{2} - 36 )}

What is the domain of f(x)=sqrt((2|x|+3)/(x^2+1)) ?
The domain of f(x)=sqrt((2|x|+3)/(x^2+1)) is -infinity <x<infinity