What is the domain of (ln(2t+1))/t ?

The domain of (ln(2t+1))/t is -1/2 0

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domain of (ln(2t+1))/t

domain

\frac{ln ( 2 t + 1 )}{t}

- \frac{1}{2} < t < 0 or t > 0

Interval Notation

(- \frac{1}{2}, 0) \cup (0, \infty)

Solution steps

Find positive values for logs:

t > - \frac{1}{2}

Find undefined (singularity) points:

t = 0

Combine real regions and undefined points for final function domain

- \frac{1}{2} < t < 0 or t > 0

f (x) = 2900

y = x + 4 + 5 x^{2} - 2 x

f (x) = x^{4} - 4 x^{3} - 2 x^{2} + 12 x + 9

f (x) = x, x \geq 0

f (x) = \frac{5}{x ^{2} - 3 x - 10}

What is the domain of (ln(2t+1))/t ?
The domain of (ln(2t+1))/t is -1/2 <t<0\lor t>0