What is the domain of 1/(sqrt(x+3)+2) ?

The domain of 1/(sqrt(x+3)+2) is x>=-3

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domain of 1/(sqrt(x+3)+2)

domain

\frac{1}{x + 3 + 2}

x \geq - 3

Interval Notation

[- 3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

The function domain

x \geq - 3

f (x) = \frac{2 x ^{2} - x + 1}{x - 1}

\frac{2 x}{10 x + 1}

y = (\frac{4}{5})^{x}

\frac{x + 6}{x - 6}

f (x) = - e^{\frac{1}{5} x}