What is the domain of (sqrt(2x-5))(sqrt(9-x)) ?

The domain of (sqrt(2x-5))(sqrt(9-x)) is 5/2 <= x<= 9

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domain of (sqrt(2x-5))(sqrt(9-x))

domain

(2 x - 5) (9 - x)

\frac{5}{2} \leq x \leq 9

Interval Notation

[\frac{5}{2}, 9]

Solution steps

Find non-negative values for radicals:

\frac{5}{2} \leq x \leq 9

The function domain

\frac{5}{2} \leq x \leq 9

x^{2} - 4, x \leq - 2

y = - 2 x + 4

y = - 2 x + 2

y = - 2 x + 3

\frac{3 x ^{3} - 8 x - 3}{x - 3}

What is the domain of (sqrt(2x-5))(sqrt(9-x)) ?
The domain of (sqrt(2x-5))(sqrt(9-x)) is 5/2 <= x<= 9