What is the domain of f(x)= 1/(x*sqrt(1-x^2)) ?

The domain of f(x)= 1/(x*sqrt(1-x^2)) is -1<x<0\lor 0<x<1

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domain of f(x)= 1/(x*sqrt(1-x^2))

domain

f (x) = \frac{1}{x \cdot 1 - x ^{2}}

- 1 < x < 0 or 0 < x < 1

Interval Notation

(- 1, 0) \cup (0, 1)

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

Find undefined (singularity) points:

x = 0, x = 1, x = - 1

Combine real regions and undefined points for final function domain

- 1 < x < 0 or 0 < x < 1

f (x) = \frac{( x ^{2} - 9 )}{x + 4}

y = - 5 - 3 x - 15 - 6

f (x) = x^{2} + 10 x + 2

f (x) = x^{2} + 10 x + 6

f (x) = - 2 (4) cos (6^{2} x + \frac{π}{4}) - 2

What is the domain of f(x)= 1/(x*sqrt(1-x^2)) ?
The domain of f(x)= 1/(x*sqrt(1-x^2)) is -1<x<0\lor 0<x<1