What is the domain of f(x)=x^3-1+sqrt(x+1) ?

The domain of f(x)=x^3-1+sqrt(x+1) is x>=-1

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domain of f(x)=x^3-1+sqrt(x+1)

domain

f (x) = x^{3} - 1 + x + 1

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

f (x) = 9 (x + 3)^{2} + 4 (y - 5) 2 = 36

f (x) = x - 5 + x + 3

\frac{1}{3} ln (x) + 6

\frac{x ^{4} + 3 x + x ^{2} + 1}{x}

f (x) = 2 (y - 5)^{2} + 8

What is the domain of f(x)=x^3-1+sqrt(x+1) ?
The domain of f(x)=x^3-1+sqrt(x+1) is x>=-1