What is the domain of f(x)=3x+1,0<x<5 ?

The domain of f(x)=3x+1,0<x<5 is 0<x<5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=3x+1,0<x<5

domain

f (x) = 3 x + 1, 0 < x < 5

0 < x < 5

Interval Notation

(0, 5)

Solution steps

Set the domain to the given interval

0 < x < 5

The function has no undefined points nor domain constraints. Therefore, the domain is

0 < x < 5

y = \frac{x - 8}{- 5}

(- 4 x^{2} + 3 x) (3 x - 5)

4 - 2 ∣ x ∣

2 π r^{2} + 2 π r h

\frac{6 x - 18}{x ^{2} + 5 x}