What is the domain of f(x)=ln((x-2)/(x+3)) ?

The domain of f(x)=ln((x-2)/(x+3)) is x 2

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domain of f(x)=ln((x-2)/(x+3))

domain

f (x) = ln (\frac{x - 2}{x + 3})

x < - 3 or x > 2

Interval Notation

(- \infty, - 3) \cup (2, \infty)

Solution steps

Find positive values for logs:

x < - 3 or x > 2

Find undefined (singularity) points:

x = - 3

Combine real regions and undefined points for final function domain

x < - 3 or x > 2

tan (x + 2)

f (x) = 8 - 3 x - (x - 4)

\frac{\frac{x}{x + 6}}{\frac{x}{x + 6} + 6}

f (x) = - (2 x - 2)^{2} + 3

\frac{x}{x ^{2} - 4}

What is the domain of f(x)=ln((x-2)/(x+3)) ?
The domain of f(x)=ln((x-2)/(x+3)) is x<-3\lor x>2