What is the domain of f(x)=(sqrt(x-3))/(x-4) ?

The domain of f(x)=(sqrt(x-3))/(x-4) is 3 4

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domain of f(x)=(sqrt(x-3))/(x-4)

domain

f (x) = \frac{x - 3}{x - 4}

3 \leq x < 4 or x > 4

Interval Notation

[3, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

3 \leq x < 4 or x > 4

f (x) = \frac{( x + 5 )}{x ^{2} - 25}

f (x) = \frac{1 + x - 1 - x}{x}

30 - x

f (x) = - 2 x^{2} + 8 x + 9

y = \frac{7 x - 8}{6 x + 5}

What is the domain of f(x)=(sqrt(x-3))/(x-4) ?
The domain of f(x)=(sqrt(x-3))/(x-4) is 3<= x<4\lor x>4