What is the domain of f(x)=sqrt(3x-12)+6/(x-3) ?

The domain of f(x)=sqrt(3x-12)+6/(x-3) is x>= 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(3x-12)+6/(x-3)

domain

f (x) = 3 x - 12 + \frac{6}{x - 3}

x \geq 4

Interval Notation

[4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

x \geq 4

f (x) = \frac{- 2 x - 5}{3 x + 18}

0.2 x^{2} + 5 - x

f (x) = 7^{x - 20} - 40

f (x, y) = \frac{1}{x ^{2} + 1}

\frac{( \frac{1}{28 - x} )}{x + 29}

What is the domain of f(x)=sqrt(3x-12)+6/(x-3) ?
The domain of f(x)=sqrt(3x-12)+6/(x-3) is x>= 4