What is the domain of y=(sqrt(x^2-25))/(sqrt(x^2)) ?

The domain of y=(sqrt(x^2-25))/(sqrt(x^2)) is x = 5

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domain of y=(sqrt(x^2-25))/(sqrt(x^2))

domain

y = \frac{x ^{2} - 25}{x ^{2}}

x \leq - 5 or x \geq 5

Interval Notation

(- \infty, - 5] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 5 or x \geq 5

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x \leq - 5 or x \geq 5

f (x) = arccos (\frac{- x}{2}) + \frac{π}{2}

\frac{- 16 + x}{4}

\frac{5}{3 x - 1}

f (x) = \frac{1}{0.5 arctan ( x )}

\frac{3 x ^{2} - 1}{2 x + 1} + x

What is the domain of y=(sqrt(x^2-25))/(sqrt(x^2)) ?
The domain of y=(sqrt(x^2-25))/(sqrt(x^2)) is x<=-5\lor x>= 5