What is the domain of f(x)=(2x-1)/(2x^2-25x+63) ?

The domain of f(x)=(2x-1)/(2x^2-25x+63) is x 9

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domain of f(x)=(2x-1)/(2x^2-25x+63)

domain

f (x) = \frac{2 x - 1}{2 x ^{2} - 25 x + 63}

x < \frac{7}{2} or \frac{7}{2} < x < 9 or x > 9

Interval Notation

(- \infty, \frac{7}{2}) \cup (\frac{7}{2}, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

x = 9, x = \frac{7}{2}

The function domain

x < \frac{7}{2} or \frac{7}{2} < x < 9 or x > 9

ln (x - 1) + ln (x + 2)

f (x) = \frac{5}{4} x - 3

f (x) = 1 - 3 cos (x)

ln (x^{2} + x - 20)

f (x) = \frac{x ^{2} + 5 x + 6}{x ^{2} + 2 x - 8}

What is the domain of f(x)=(2x-1)/(2x^2-25x+63) ?
The domain of f(x)=(2x-1)/(2x^2-25x+63) is x< 7/2 \lor 7/2 <x<9\lor x>9