What is the domain of f(x)=sqrt(x-2)+(3x+8)/(x-6) ?

The domain of f(x)=sqrt(x-2)+(3x+8)/(x-6) is 2 6

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domain of f(x)=sqrt(x-2)+(3x+8)/(x-6)

domain

f (x) = x - 2 + \frac{3 x + 8}{x - 6}

2 \leq x < 6 or x > 6

Interval Notation

[2, 6) \cup (6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 6

Combine real regions and undefined points for final function domain

2 \leq x < 6 or x > 6

f (y) = \frac{5}{2}

f (x) = \frac{x ^{2} - 7}{4}

y = - x (x - 2)^{4} (x + 3)

\frac{4}{3 x ^{2} + 1}

f (x) = 9 + lo g_{2} (x)

What is the domain of f(x)=sqrt(x-2)+(3x+8)/(x-6) ?
The domain of f(x)=sqrt(x-2)+(3x+8)/(x-6) is 2<= x<6\lor x>6