What is the domain of f(x)=(x+1)/(x^2-36) ?

The domain of f(x)=(x+1)/(x^2-36) is x 6

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domain of f(x)=(x+1)/(x^2-36)

domain

f (x) = \frac{x + 1}{x ^{2} - 36}

x < - 6 or - 6 < x < 6 or x > 6

Interval Notation

(- \infty, - 6) \cup (- 6, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = - 6

The function domain

x < - 6 or - 6 < x < 6 or x > 6

y = \frac{x ^{2} - 5 x + 2}{x ^{2} + 1}

- 3 x - 2 + 4

\frac{( 1 )}{( x ( x - 1 ) ( x + 3 ) )}

3 - x + 8

f (x) = ln (0.5 + x)

What is the domain of f(x)=(x+1)/(x^2-36) ?
The domain of f(x)=(x+1)/(x^2-36) is x<-6\lor-6<x<6\lor x>6