What is the domain of f(x)= 1/(2xsqrt(6+ln(x))) ?

The domain of f(x)= 1/(2xsqrt(6+ln(x))) is x> 1/(e^6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(2xsqrt(6+ln(x)))

domain

f (x) = \frac{1}{2 x 6 + ln ( x )}

x > \frac{1}{e ^{6}}

Interval Notation

(\frac{1}{e ^{6}}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{e ^{6}}

Find undefined (singularity) points:

x = \frac{1}{e ^{6}}

Combine real regions and undefined points for final function domain

x > \frac{1}{e ^{6}}

\frac{x + 4 x ^{3}}{x ^{2} - 2 x ^{3}}

ln (x - x^{2} + 1)

f (x) = x^{2} - 4 - 4 x - x^{2}

f (x) = 9 x

What is the domain of f(x)= 1/(2xsqrt(6+ln(x))) ?
The domain of f(x)= 1/(2xsqrt(6+ln(x))) is x> 1/(e^6)