What is the domain of f(x)=(3+\sqrt[4]{x-2})/5 ?

The domain of f(x)=(3+\sqrt[4]{x-2})/5 is x>= 2

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domain of f(x)=(3+\sqrt[4]{x-2})/5

domain

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

\frac{1}{ln ( ( x - 1 ) ^{2} ) - 1}

f (x) = \frac{4}{x + 1} + 5

f (x) = 8 x^{2} - x^{4}

f (x) = 72 - x^{2} + x

f (x) = \frac{x - 3 x - 10}{x ^{2} - 16}

What is the domain of f(x)=(3+\sqrt[4]{x-2})/5 ?
The domain of f(x)=(3+\sqrt[4]{x-2})/5 is x>= 2