What is the domain of f(x)= 1/(-ln(x)-1/2) ?

The domain of f(x)= 1/(-ln(x)-1/2) is 0 1/(sqrt(e))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(-ln(x)-1/2)

domain

f (x) = \frac{1}{- ln ( x ) - \frac{1}{2}}

0 < x < \frac{1}{e} or x > \frac{1}{e}

Interval Notation

(0, \frac{1}{e}) \cup (\frac{1}{e}, \infty)

Solution steps

Find positive values for logs:

x > 0

Find undefined (singularity) points:

x = \frac{1}{e}

Combine real regions and undefined points for final function domain

0 < x < \frac{1}{e} or x > \frac{1}{e}

f (x) = 3 arcsin (x)

f (x) = 1 x + 18

\frac{x}{( 3 - x ) ( x + 2 )}

f (x) = (x - 3)^{2} - (x - 8)^{2}

18 x - 9 x^{2} - 9

What is the domain of f(x)= 1/(-ln(x)-1/2) ?
The domain of f(x)= 1/(-ln(x)-1/2) is 0<x< 1/(sqrt(e))\lor x> 1/(sqrt(e))