What is the domain of f(x)=sqrt((1+x)/(9-x)) ?

The domain of f(x)=sqrt((1+x)/(9-x)) is -1<= x<9

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domain of f(x)=sqrt((1+x)/(9-x))

domain

f (x) = \frac{1 + x}{9 - x}

- 1 \leq x < 9

Interval Notation

[- 1, 9)

Solution steps

Find non-negative values for radicals:

- 1 \leq x < 9

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

- 1 \leq x < 9

f (x) = e^{0.5 x} + 576 e^{- 0.5 x}

\frac{x - 5}{3} + 4

f (x) = \frac{- 7 x - 2}{4 x + 7}

f (x) = x^{2} 4 - x

f (x) = \frac{x + 1}{3 x ^{2} - 27}

What is the domain of f(x)=sqrt((1+x)/(9-x)) ?
The domain of f(x)=sqrt((1+x)/(9-x)) is -1<= x<9