What is the domain of f(x)=(-5x^2)/((x-9)(x+4)) ?

The domain of f(x)=(-5x^2)/((x-9)(x+4)) is x 9

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domain of f(x)=(-5x^2)/((x-9)(x+4))

domain

f (x) = \frac{- 5 x ^{2}}{( x - 9 ) ( x + 4 )}

x < - 4 or - 4 < x < 9 or x > 9

Interval Notation

(- \infty, - 4) \cup (- 4, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

x = 9, x = - 4

The function domain

x < - 4 or - 4 < x < 9 or x > 9

y = \frac{4 x + 1}{2 x + 3} - \frac{3 x + 2}{5 x - 1}

\frac{( x ^{2} - 3 x + 2 )}{x ^{2} + x - 6}

\frac{( x - 3 ) ^{2}}{2}

g (x) = lo g_{10} (x - x^{2})

ln (16 - y^{2})

What is the domain of f(x)=(-5x^2)/((x-9)(x+4)) ?
The domain of f(x)=(-5x^2)/((x-9)(x+4)) is x<-4\lor-4<x<9\lor x>9