What is the domain of (sqrt(x^2-1))/(x^2+5) ?

The domain of (sqrt(x^2-1))/(x^2+5) is x = 1

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domain of (sqrt(x^2-1))/(x^2+5)

domain

\frac{x ^{2} - 1}{x ^{2} + 5}

x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 1] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

The function domain

x \leq - 1 or x \geq 1

2 - 6 - x - x^{2}

5 x^{3} - 17 x^{2} + 6 x

∣ x - 1 ∣ + ∣ x - 2 ∣

f (x) = \frac{3 x + 1}{2 x + 1}

y = 5 (2 (x + 7))^{2}

What is the domain of (sqrt(x^2-1))/(x^2+5) ?
The domain of (sqrt(x^2-1))/(x^2+5) is x<=-1\lor x>= 1