What is the domain of y=(3x^2)/(sqrt(x^3-3^2)) ?

The domain of y=(3x^2)/(sqrt(x^3-3^2)) is x>\sqrt[3]{9}

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domain of y=(3x^2)/(sqrt(x^3-3^2))

domain

y = \frac{3 x ^{2}}{x ^{3} - 3 ^{2}}

Interval Notation

Solution steps

Find non-negative values for radicals:

Find undefined (singularity) points:

Combine real regions and undefined points for final function domain

f (x) = \frac{( x + 1 ) ^{2}}{( x - 1 ) ^{2}}

x^{2} + x + 1 - x^{2} - x - 12 + 2

f (x) = \frac{1}{2} (x^{3} - 3 x + 7)

\frac{11250 + 180 x ^{3}}{x}

y = 5 x^{3} - 5 x + 1

What is the domain of y=(3x^2)/(sqrt(x^3-3^2)) ?
The domain of y=(3x^2)/(sqrt(x^3-3^2)) is x>\sqrt[3]{9}