What is the inverse of f(x)=2(x-1)^2+6 ?

The inverse of f(x)=2(x-1)^2+6 is sqrt((x-6)/2)+1,-sqrt((x-6)/2)+1

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inverse of f(x)=2(x-1)^2+6

inverse

f (x) = 2 (x - 1)^{2} + 6

\frac{x - 6}{2} + 1, - \frac{x - 6}{2} + 1

Solution steps

y = 2 (x - 1)^{2} + 6

Replace

x

with

y

x = 2 (y - 1)^{2} + 6

Solve for

y, x = 2 (y - 1)^{2} + 6

\frac{x - 6}{2} + 1, - \frac{x - 6}{2} + 1

f (x) = ∣ x ∣ + 3

x^{2} - 2 x - 2

x^{3} + 8

4 - x^{3}

x + 1 - \frac{1}{x}

What is the inverse of f(x)=2(x-1)^2+6 ?
The inverse of f(x)=2(x-1)^2+6 is sqrt((x-6)/2)+1,-sqrt((x-6)/2)+1