What is the domain of 8/(x^3)-4/(x^1) ?

The domain of 8/(x^3)-4/(x^1) is x 0

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domain of 8/(x^3)-4/(x^1)

domain

\frac{8}{x ^{3}} - \frac{4}{x ^{1}}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

\frac{4}{x - 9}

2 cos (x) - sin (2 x)

f (t) = - 3 t

1 - 2^{t}

f (x) = 6 - \frac{3}{x ^{5}}

What is the domain of 8/(x^3)-4/(x^1) ?
The domain of 8/(x^3)-4/(x^1) is x<0\lor x>0