What is the domain of f(x)=(82)/((9x-1)^2) ?

The domain of f(x)=(82)/((9x-1)^2) is x 1/9

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domain of f(x)=(82)/((9x-1)^2)

domain

f (x) = \frac{82}{( 9 x - 1 ) ^{2}}

x < \frac{1}{9} or x > \frac{1}{9}

Interval Notation

(- \infty, \frac{1}{9}) \cup (\frac{1}{9}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{9}

The function domain

x < \frac{1}{9} or x > \frac{1}{9}

\frac{7 x + 9}{x ^{2} - 9} - \frac{6 x + 6}{x ^{2} - 9}

f (x) = \frac{( x - 5 )}{x ^{2} + 4 x}

(6.5) (7.7)

2 sin (4 x)

cos^{6} (x)

What is the domain of f(x)=(82)/((9x-1)^2) ?
The domain of f(x)=(82)/((9x-1)^2) is x< 1/9 \lor x> 1/9