What is the domain of f(x)=(x^2+2x-8)/(sqrt(x^{44))} ?

The domain of f(x)=(x^2+2x-8)/(sqrt(x^{44))} is x 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x^2+2x-8)/(sqrt(x^{44))}

domain

f (x) = \frac{x ^{2} + 2 x - 8}{x ^{44}}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 0

f (x) = \frac{- 6 x ^{2}}{( x - 2 ) ( x + 6 )}

Y (x) = 2 x + 4

f (x) = \frac{2 x}{3 x - 6}

7 - x^{3}

f (x) = lo g_{∣ x ∣ - 4} (2 - x)

What is the domain of f(x)=(x^2+2x-8)/(sqrt(x^{44))} ?
The domain of f(x)=(x^2+2x-8)/(sqrt(x^{44))} is x<0\lor x>0