What is the domain of f(x)=-(2x)/(x+1)+1=-1/(x+1) ?

The domain of f(x)=-(2x)/(x+1)+1=-1/(x+1) is x -1

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domain of f(x)=-(2x)/(x+1)+1=-1/(x+1)

domain

f (x) = - \frac{2 x}{x + 1} + 1 = - \frac{1}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = lo g_{10} (3) (x + 4)

f (x) = \frac{9 ( 5 + x )}{4}

f (x) = 1 + ln (x^{3} + 1)

f (x) = \frac{1}{4} lo g_{10} (x - 3) - 6

f (x) = \frac{x + 2}{3}

What is the domain of f(x)=-(2x)/(x+1)+1=-1/(x+1) ?
The domain of f(x)=-(2x)/(x+1)+1=-1/(x+1) is x<-1\lor x>-1