What is the domain of y= 1/(x(3-x^2)) ?

The domain of y= 1/(x(3-x^2)) is x sqrt(3)

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domain of y= 1/(x(3-x^2))

domain

y = \frac{1}{x ( 3 - x ^{2} )}

x < - 3 or - 3 < x < 0 or 0 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 0) \cup (0, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 3, x = 3

The function domain

x < - 3 or - 3 < x < 0 or 0 < x < 3 or x > 3

f (x) = \frac{21 - 2 x}{x - 9}

6 - x^{2}

f (x) = - 2 x + 4

f (x) = \frac{2 x - 1}{x ^{2} - 2 x + 1}

f (x) = \frac{x ^{2} + 17 x + 72}{x ^{2} + 2 x - 80}

What is the domain of y= 1/(x(3-x^2)) ?
The domain of y= 1/(x(3-x^2)) is x<-sqrt(3)\lor-sqrt(3)<x<0\lor 0<x<sqrt(3)\lor x>sqrt(3)