What is the domain of 4-1/((x+1)^2) ?

The domain of 4-1/((x+1)^2) is x -1

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domain of 4-1/((x+1)^2)

domain

4 - \frac{1}{( x + 1 ) ^{2}}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

\frac{6 x}{x - 3}

\frac{x - 4}{x ^{2} + 5 x - 14}

f (x) = \frac{1}{x} - 1 - x^{2}

f (x) = x - ∣ 2 x - 3 ∣

y = - \frac{3}{x - 1} + 1

What is the domain of 4-1/((x+1)^2) ?
The domain of 4-1/((x+1)^2) is x<-1\lor x>-1