What is the domain of \sqrt[4]{(2x-1)/(4x-3)} ?

The domain of \sqrt[4]{(2x-1)/(4x-3)} is x 3/4

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domain of \sqrt[4]{(2x-1)/(4x-3)}

domain

x \leq \frac{1}{2} or x > \frac{3}{4}

Interval Notation

(- \infty, \frac{1}{2}] \cup (\frac{3}{4}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq \frac{1}{2} or x > \frac{3}{4}

Find undefined (singularity) points:

x = \frac{3}{4}

Combine real regions and undefined points for final function domain

x \leq \frac{1}{2} or x > \frac{3}{4}

x + e^{x}

f (x) = 3 x^{3} - 1

f (x) = lo g_{10} (4) (x + 3)

f (x) = \frac{- 2 - 9 x}{5 x - 3}

f (x) = 5 x + 10 y = 20

What is the domain of \sqrt[4]{(2x-1)/(4x-3)} ?
The domain of \sqrt[4]{(2x-1)/(4x-3)} is x<= 1/2 \lor x> 3/4