What is the domain of f(a)= 1/((x+2)^2) ?

The domain of f(a)= 1/((x+2)^2) is x -2

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domain of f(a)= 1/((x+2)^2)

domain

f (a) = \frac{1}{( x + 2 ) ^{2}}

x < - 2 or x > - 2

Interval Notation

(- \infty, - 2) \cup (- 2, \infty)

Solution steps

Find undefined (singularity) points:

x = - 2

The function domain

x < - 2 or x > - 2

f (x) = 2 (x + 4)^{2} - 5

\frac{8 x - 1}{x + 9}

f (x) = \frac{2 ^{x} - 2 ^{- x}}{2 ^{x} + 2 ^{- x}}

f (x) = \frac{x - 7}{2}

f (x) = \frac{- x - 10}{x ^{3}}

What is the domain of f(a)= 1/((x+2)^2) ?
The domain of f(a)= 1/((x+2)^2) is x<-2\lor x>-2