What is the domain of 3/4 log_{3}(x-1)+9 ?

The domain of 3/4 log_{3}(x-1)+9 is x>1

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domain of 3/4 log_{3}(x-1)+9

domain

\frac{3}{4} lo g_{3} (x - 1) + 9

x > 1

Interval Notation

(1, \infty)

Solution steps

Find positive values for logs:

x > 1

The function domain

x > 1

\frac{1}{x ^{2} + 10 x + 9}

12 x (x + 1) (x - 1)

f (x) = \frac{- x ^{2} + 3 x - 2}{2 x - 4}

f (x) = 20 x + 27

What is the domain of 3/4 log_{3}(x-1)+9 ?
The domain of 3/4 log_{3}(x-1)+9 is x>1