What is the domain of f(x)=(4-x^2)/(5x^2-3) ?

The domain of f(x)=(4-x^2)/(5x^2-3) is x sqrt(3/5)

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domain of f(x)=(4-x^2)/(5x^2-3)

domain

f (x) = \frac{4 - x ^{2}}{5 x ^{2} - 3}

x < - \frac{3}{5} or - \frac{3}{5} < x < \frac{3}{5} or x > \frac{3}{5}

Interval Notation

(- \infty, - \frac{3}{5}) \cup (- \frac{3}{5}, \frac{3}{5}) \cup (\frac{3}{5}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{5}, x = - \frac{3}{5}

The function domain

x < - \frac{3}{5} or - \frac{3}{5} < x < \frac{3}{5} or x > \frac{3}{5}

f (x) = 6 n - 24

f (x) = \frac{2 x + 3}{7 - 5 x}

f (x) = \frac{8 x ^{2}}{16 - x ^{2}}

h (x) = 30 - 5 x

f (x) = 2 + 2 x

What is the domain of f(x)=(4-x^2)/(5x^2-3) ?
The domain of f(x)=(4-x^2)/(5x^2-3) is x<-sqrt(3/5)\lor-sqrt(3/5)<x<sqrt(3/5)\lor x>sqrt(3/5)