What is the domain of f(x)=(x^3-3)/(sqrt(x^4+1)) ?

The domain of f(x)=(x^3-3)/(sqrt(x^4+1)) is -infinity <x<infinity

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domain of f(x)=(x^3-3)/(sqrt(x^4+1))

domain

f (x) = \frac{x ^{3} - 3}{x ^{4} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

(x)

f (x) = \frac{x ^{2} - 7 x + 10}{6 x + 1}

\frac{2 x + 3}{x + 3}

f (x) = 2 + 3 x

- \frac{1}{3} - \frac{7}{3}

What is the domain of f(x)=(x^3-3)/(sqrt(x^4+1)) ?
The domain of f(x)=(x^3-3)/(sqrt(x^4+1)) is -infinity <x<infinity