What is the domain of sqrt(2x+17) ?

The domain of sqrt(2x+17) is x>=-17/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt(2x+17)

domain

2 x + 17

x \geq - \frac{17}{2}

Interval Notation

[- \frac{17}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{17}{2}

The function domain

x \geq - \frac{17}{2}

(4 x + 5) - (x + 9)

f (x) = 4 x^{3} - 40 x^{2} + 96 x

- ∣ x - 5 ∣ + 5

2 x + 16

f (x) = \frac{x}{x ^{2} + 5 x - 36}