What is the domain of y=(9x)/(x^2+4x-5) ?

The domain of y=(9x)/(x^2+4x-5) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(9x)/(x^2+4x-5)

domain

y = \frac{9 x}{x ^{2} + 4 x - 5}

x < - 5 or - 5 < x < 1 or x > 1

Interval Notation

(- \infty, - 5) \cup (- 5, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 5

The function domain

x < - 5 or - 5 < x < 1 or x > 1

f (x) = \frac{3 x}{8}

f (x) = 5 x^{4} - 30 x^{2}

y = \frac{5 x - 2}{3 + 2 x}

e^{x} cos (x)

f (x) = 1 + \frac{2 x}{x ^{2} - 3}

What is the domain of y=(9x)/(x^2+4x-5) ?
The domain of y=(9x)/(x^2+4x-5) is x<-5\lor-5<x<1\lor x>1